8y^2-7y-1=0

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Solution for 8y^2-7y-1=0 equation: 



8y^2-7y-1=0

a = 8; b = -7; c = -1;
Δ = b2-4ac
Δ = -72-4·8·(-1)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*8}=\frac{-2}{16}
=-1/8
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*8}=\frac{16}{16}
=1
$

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